A body thrown vertically so as to reach its
maximum height in t second. The total time
from the time of projection to reach a point at
half of its maximum height while returning (in
second) is:
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11th
Physics
Motion in a Straight Line
Problems on Equation of Motion
A body is thrown vertically...
PHYSICS
A body is thrown vertically up to reach its maximum height in t seconds. The total time from the time of projection to reach a point at half of its maximum height while returning ( in seconds ) is
December 30, 2019avatar
Sonakshi Dhage
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ANSWER
At max
m
height v=o,
v=u−gt,⇒t=
g
u
=
g
2H
−(1)
Now situation is,
We want time to reach C.
Time from AtoB=t
Time from BtoC⇒v
c
2
=v
B
2
+2g
2
H
2
H
=+
2
1
gt
1
2
v
C
=
gH
t
1
=
g
H
⇒t
1
=
2
t
(from(1))
So, total time =t+t
1
=t+
2
t
=t(1+
2
1
)
Explanation:
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