Question

A body thrown vertically up from the ground passes the height 10.2 m twice at an interval of 10 sec.
Its initial velocity was (g=10m/s?)
1) 52 m/s
2)26 m/s
3) 35 m/s
4) 60 m/s​

Answer 1

Explanation:

h=10.2m

t=10/2=5s

g=10m/s^2.

u=?

h=ut-1/2*gt^2

10.2=5u-1/2*10*25

10.2+125=5u

135.2/5=u

u=27m/s