A body thrown vertically up with initial velocity 52 m/s from the ground passes twice a point at h height above at an interval of 10 s. The height h is ( g= 10 m/ ss)
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Given that the body is thrown up with initial velocity , u = 52 m/s
it passes twice a point of height h in t= 10 sec.
Therefore :
As it passes twice a point of height H , we can write S =2 h = 20 m
2 h = 20 m
h = 10 m
The height h= 10 m
it passes twice a point of height h in t= 10 sec.
Therefore :
As it passes twice a point of height H , we can write S =2 h = 20 m
2 h = 20 m
h = 10 m
The height h= 10 m
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