Question

A body thrown vertically up with initial velocity 52 metre per second from the ground passes through a point at its height above at an interval of 10 second the height h is







no one has its right answer up till now​

Answer 1

Answer:

Initial velocity, V=52m/s

Time taken, t=10sec

⇒S=ut+

2

1

at

2

=52(10)−

2

1

(10)(100)

=20m

As, S=2h

⇒h=10m

Hence, the answer is 10m.