a body thrown vertically upward and returns back to the thrower after 6 sec find the velocity by which it is thrown
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consider it as a projectile motion with theta 90 degree Then T=2usin theta/g
6=2usin90/g
u=3g
6=2usin90/g
u=3g
jatt4:
good
Answered by
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As in projectile motion
T=2usin theta/g
6=2usin90/g
u=3g
Plzzz mark it as brainliest
dude u jst copy pasted my comment! I am reporting you.
Hey I knw that solution . u had answerd first that's not my fault
Not really. You knowing a solution is alright. You TYPED/COPIED it EXACTLY as I did in above. That is not possible since I was in mob I couldn't provide a neat writing. Please don't lie. Let's wait for moderator action :) Cheers!
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