Question

a body thrown vertically upward with an initial velocity of 19.6 meters per second calculate the following the maximum height attained in the body after how much time will it come back to the ground

Answer 1

Answer:

maximum height = 19.6 m

time taken = 4 sec

Explanation:

Given :

A body is thrown vertically upward with initial velocity of the body, u = 19.6 m/s

To find :

• the maximum height attained by the body
• the time taken to come back to the ground

Solution :

Acceleration due to gravity, g = 9.8 m/s²

The maximum height of the body thrown vertically upwards is given by,

$\boxed{ \bf h = \dfrac{ {u}^{2} }{2g} }$

Substitute the values,

h = 19.6 × 19.6/2(9.8)

h = 19.6 m

Therefore, the maximum height attained by the body is 19.6 m

The time taken to come back to the ground by the body is given by,

$\boxed{ \bf \: t = \frac{2u}{g} }$

Substitute the values,

t = 2(19.6) /9.8

t = 2(2)

t = 4 s

Therefore, the time taken by the body to come back to the ground is 4 sec