Question

A body thrown vertically upwards reaches a maximum height h. It then returns to ground.calculate the distance travelled and the displacement.....​

Answer 1

Displacement is the actual length gap between starting & finishing points.

In this case, they are same, so

Net displacement is zero.

Distance travelled is the length which is actually covered by the moving body.

As the body goes up for "h" length and comes down "h" length, so

Net distance travelled= h+ h= 2h

Hope it was easy for you

and please mark me as brainliest

Answer 2

let the body is thrown with u initial velocity after reaching at highest point its velocity become zero

apply equation of motion

v^2-u^2=2as

0-u^2=-2gs

s=u^2/2g

if the body was thrown from the earth surface then it will cover 2s distance i.e,u^2/g and displacement would be zero

and if it was thrown from height h then it will cover distance after reaching on earth surface i.e,u^2/g + h
and displacement would be -h