a body thrown vertically upwards reachs the maximum height. then it returns to ground caculate the distance and displacement.
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Answered by
2
since the body returns to its initial position therefore the displacement is 0.
the distance traveled is 2h_max=u^2/g
the distance traveled is 2h_max=u^2/g
Answered by
1
As we know that the total length of journey is the distance .
Distance= h+h =2h
Also we know that the shortest distance between initial and final positions the body is coming back to the initial position the net displacement is zero
hope u got me
Distance= h+h =2h
Also we know that the shortest distance between initial and final positions the body is coming back to the initial position the net displacement is zero
hope u got me
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