Question

a body throws a ball with a velocity of 20 metre per second find the time elapsed between the throwing and catching the ball​

Answer 1

Answer:

The time elapsed between the throwing and catching the ball = 4.08 seconds

Explanation:

we will assume that the ball is thrown vertically upward and caught at the same place.

I this case the ball will go upward till it's velocity becomes 0 m/ s then it will free fall .

v = u + at

v - final velocity = 0

u - initial velocity = 20

t - time

a- acceleration or retardation due to gravity

t = ( v - u ) ÷ a

= ( 0 - 20) ÷ (- 9.80 )

-20

= -------------

- 9.8

= 20 ÷9.8

= 2.04 seconds

now this will free fall from there

and will take same time to be caught = 2.04 seconds

So the time elapsed between the throwing and catching the ball = 2.04 +2.04 = 4.08 seconds