Question

A body tied to a string of length l is revolved in a vertical circle with minimum

Answer 1

Answer:

R = 2L

Explanation:

To understand the question, first read below question statement(full)

A object is tied to the string of length and is revolved

in a vertical circle at minimum velocity when the object

reaches the upper most point the strings breaks and it

describes a parabolic path as shown in figure under

gravitational force. The horizontal range AC in the plane

of A would be​

Solution

First see the attached figure;

If the height is taken as h = 2L, then it can be meant that the body is thrown from a height of 2L.  

The vertical motion of the body is u=\sqrt{g l}

The above statement shows that the Range is R = u x t

Therefore, the range, R can be calculated as R = u x t

R =  

Now the value of time, \mathrm{t}=\sqrt{\frac{2 h}{g}}

Therefore, the range “R” = u \sqrt{\frac{2 h}{g}}=\frac{\sqrt{g L .4 L}}{\sqrt{g}}=2 L

The value of u in the above equation is taken as u=\sqrt{g l} and the h = 2L.

Therefore, the range, R = 2L.