Question

A body traveeling at velocity 12.5km hr comes to rest on applying brakes in 5 mins find its de accelaration

Answer 1

Answer:

u= 12.5km= 12.5× 10^3

t=5 min

a=?

V=0

Explanation:

use v=u+at

put value and solve it..you will get your answer.

Answer 2

Answer:

Us ethe formula

$v = u + at$

here v is 0

u is 12.5

t is 5mins

v = u + at

0 = 12.5 + 5a

5a = -12.5

a = -2.5

-ve sign denotes that acceleration is in opposite direction i.e. it is retardation

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