Question

a body travel a distance of 2 m in 2 sec 2.2 m in next 4 sec what will be the velocity at the end of 10 sec from the start
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Answer 1

Question:-

A body travel a distance of 2 m in 2 sec 2.2 m in next 4 sec what will be the velocity at the end of 10 sec from the start.

Solution:-

Let the initial velocity be u and acceleration be a.

Thus distance travelled in 2sec is 2m , using 2nd equation of motion:

2 = u(2) + 1/2 a(2)²

1 = u + a ........(1)

also distance in four seconds i.e between 6th and 2nd seconds is 2 .2 m

2.2 = u(6) + 1/2 a (6)² - 2 = 2.2

6u + 18a = 4.2

0.7 = u + 3a ........(2)

(2) – (1)

2a = 0.7 - 1

2a = -0.3

a = -0.3/2

a = -0.15m/s²

from equation (1)

u + a = 1

u = 1 - (-0.15)

u = 1.15m/s

∴ v = u + at

v = 1.15 - 0.15(10)

v = 1.15 -1.5

v = -0.35m/s