A body travel a distance of 2metre in 2 sec and 2.2 metre in next 4 sec. What will be the velocity of the body at the end of the 7second from the start
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Given
Two cases
At first case s = 2 and t=2
At second case s=2.2 and t=4
Wkt
s= ut + 1/2 a t^2
2 = u 2 + 1/2 a 2^2
1= u + a ...... 1
Total distance
2+2.2 =4.2
4.2 = u *7 + 1/2 a *7*7
8.4 = 14 u + 49 a ......2
Solving 1 and 2 l
u+a= 1
14 u + 49 a = 8.4
After solving We get
U=1.16 and a = -0.16
After 7 second velocity
V= 1.15-0.16*7
V=0.04 m/s
________________
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Plz mark as best
____________
Here is Ur answer
Given
Two cases
At first case s = 2 and t=2
At second case s=2.2 and t=4
Wkt
s= ut + 1/2 a t^2
2 = u 2 + 1/2 a 2^2
1= u + a ...... 1
Total distance
2+2.2 =4.2
4.2 = u *7 + 1/2 a *7*7
8.4 = 14 u + 49 a ......2
Solving 1 and 2 l
u+a= 1
14 u + 49 a = 8.4
After solving We get
U=1.16 and a = -0.16
After 7 second velocity
V= 1.15-0.16*7
V=0.04 m/s
________________
Hope it's helpful for u
Plz mark as best
RajatSuyal:
but the answer is 0.1
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