a body travel in a circular path with radius 1 m and it covered a distance of 3 pi / 2 . find its displacement.
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Answer:
√2 Meters
Explanation:
Radius of the circular path = 1 m
distance covered = 3π/2 ....(circular manner)
Thus angle made at center is equal to measure of arc
Central angle => 3π/2 = 270 deg
The displacement is the length of the chord and not the complete circumference of the circle ....(Refer the image attached)
Thus the length of the chord = displacement of the body
270 deg + 90 deg = 360 deg ...(Complete circle)
Thus in ΔABC ,
AB and BC are the radii of the circle while , AC is the hypotenuse
AC is the displacement of the body ...!
Angle between AB and BC is 90 deg, thus ΔABC is right angled triangle
By pythagoras Theorem
(AC)^2 = (AB)^2+(BC)^2
= (1)^2 + (1)^2
= 1 + 1
AC = √2 m
Thus the displacement of the object = √2 meters
IF YOU THINK I WAS CORRECT THEN SURELY MARK THE ANSWER AS THE BRAINLIEST ANSWER {^_^}
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