Question

A body travel it's whole journey in 2 equal time interval with speed v1 and v2 .Find out the average speed of the journey.​

Answer 1

Answer:

How's the solution buddy ?

Explanation:

Let's assume,

body travels with speed V1 from A point to B point and with speed V2 from point B to C

So, here distances are AB and BC

time=x units

As we know speed=Distance/Time, i.e, it's rate of distance traveled or covered!

Therefore, V1=AB/x and V2=BC/x___(1)

So, AB=V1*x and BC=V2*x____(from_(1))

Hence Av.Speed=Total Distance/Total Time

Therefore Av.Speed=V1*x/2x+V2*x/2x

Answer 2

Answer:

The equation is simple to derive.

Case 1: When a Body covers distance lets say ‘D’ with speed ‘v1’ time taken can calculated by the following formula.

t1 = D/v1 , ……(1)

Case 2: When a Body covers distance lets say ‘D’ with speed ‘v2’ time taken can calculated by the following formula.

t2 = D/v2 , ……(2)

Case 3: When a Body covers distance lets say ‘D’ with speed ‘v3’ time taken can calculated by the following formula.

t3 = D/v3 , ……(3)

Adding up all the three statements we can get the total time taken by the body which comes out to be

t1 + t2 + t3 ;

or D/v1 + D/v2 + D/v3 ……..(4)

And the total distance covered by the body can be easily calculated as 3D.

So Applying the formula of Average velocity or speed,

Average velocity = Total distance covered/ Total Time Taken the body

Average velocity = 3D / (D/v1 + D/v2 + D/v3)

Solving out the equation results comes out to be:

(3 * v1 * v2 * v3) / (v1v2 + v2v3 + v3v1)

Hope the formula helps you to find out the results.!!!