Question

a body traveled 25m during 6th second and 45m during 5th second find it's initial velocity and acceleration

Answer 1

Ans

distance travelled in nth sec= u +(1/2 X a (2n-1))

|) 25= u + 1/2 X a (2 X 6 -1)

25= u + (a/2) X 11 -----------------(i)

||) 45= u + (a/2) X 9 ___________(ii)

On Subtracting (ii) from (i)---

20= -2a/2

a= -20 m/s ----------acceleration

For velocity--

Putting Value of  "a" in (i) equation--

25= u+ (-20/2) X11

25= u - 110

u= 135m/s------------------(intital velocity)

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