Question

a body travell for 4 sec from rest with constant acceleration 5m/sec total distance travelled will be​

Answer 1

Answer:

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Answer 2

Answer:

Initial velocity, u=0

Initial velocity, u=0Acceleration, a=2ms −2

Initial velocity, u=0Acceleration, a=2ms −2

Initial velocity, u=0Acceleration, a=2ms −2 Time, t=5s

Initial velocity, u=0Acceleration, a=2ms −2 Time, t=5sDistance traveled, s=ut+21 at 2

Initial velocity, u=0Acceleration, a=2ms −2 Time, t=5sDistance traveled, s=ut+21 at 2

Initial velocity, u=0Acceleration, a=2ms −2 Time, t=5sDistance traveled, s=ut+21 at 2 s=(0×5)+( 21×2×52 )=25m

Explanation:

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