Question

a body travellin with a velocity of 200 ms is brought to rest in 10 sec. calculate the retardation

Answer 1

acceleration = final velocity - initial velocity/time taken
=0-200/10
=-20m/s
if acceleration is negative than retardation is positive
so retardation = 20m/s

Answer 2

HEYA!!!!!

YOUR ANSWER:
u = 200m/s
t = 10s
v = 0m/s

The formula is:

$a = (v - u) \div t$

By putting the values in it, we get:

$a = (0 - 200) \div 10$

Further solving:

$a = ( - 200) \div 10 \\ = ( - 20)m \: per \: {s}^{2}$

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