Question

A body travelling a distance of 200 m
With uniform acceleration 4m/sec? and
starting from rest. Find the time required?​

Answer 1

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Let us write the given data

Distance (s) = 200m

Acceleration (a) = 4 m/ sec

Time ( t ) = ??

Another clue/hint which is given in this question is that it is starting from rest  means initial velocity is zero

Initial velocity (u) = 0

Let us use the formula

✪ s = ut + $\frac{1}{2}$ at²

✪ 200 = 0 × t + $\frac{1}{2}$ × 4 × t²

✪  200 = 0 + 2t²

✪  200 = 2t²

✪ 200/2 = t²

✪ 100 = t²

✪ √100 = t

✪ t = 10 seconds

Hence time required is 10 seconds

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Use the newtons 3 laws of motion accornding to given quantities and find the answers . They are,

• v = u + at
• s = ut + 1/2 at²
• v² - u² = 2as

With these formulas you can apply the given quantities and find the answers

METHOD 2 :

V² - U² = 2as

v² - 0²  = 2 × 4 × 200

v² = 1600

v = √1600

v = 40

Final velocity (v) = 40 m/s

We need to find time (t)

So let us use

v = u + a t

40 = 0 + 4 t

40 = 4 t

40 / 4 = t

Time (t) = 10 seconds

#Hope it helps