a body travelling along a straight line travels one half of the total didtance with the velocity v0the remaining part of distance was covered by the velocity of v1 for half of the time and with velocit v2 for other half of the time. find the average velocity
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total distance = S
time taken for the first half of S : [ S / 2 ] / V₀ => t1 = S/(2V₀)
time taken for the second part = 1/4 th of S : [ S / 4 ] / V₁ => t2 = S/(4 V₁)
time taken for the third part : t3 = [S/4] / V₂ = S/(4V₂)
Total duration = T = S/4 * [2/V₀ + 1/V₁ + 1/V₂ ]
=> Average velocity = avg speed = S / T = 4 / [2/V₀ + 1/V₁ + 1/V₂ ]
time taken for the first half of S : [ S / 2 ] / V₀ => t1 = S/(2V₀)
time taken for the second part = 1/4 th of S : [ S / 4 ] / V₁ => t2 = S/(4 V₁)
time taken for the third part : t3 = [S/4] / V₂ = S/(4V₂)
Total duration = T = S/4 * [2/V₀ + 1/V₁ + 1/V₂ ]
=> Average velocity = avg speed = S / T = 4 / [2/V₀ + 1/V₁ + 1/V₂ ]
kvnmurty:
click on thanks button above please
it is mentioned that the time intervals for the second half distance are equal and not the distances as you have mentioned in your answer . can you please check and update your answer accordingly !!! Thank You!!!
you are right.
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here is the right answer of this question
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