Question

A body travelling along a straight line traversed one third of the total distance with velocity 4m/s the remaining part of distance was covered with velocity 2m/s for half the time and with velocity 6m/s for the next half time calculate the average speed for the entire journey

Answer 1

Answer:-

Let total distance be "d".

Let time covered for first one third distance be "t1".

Then,

$= > \bold{t1 = \frac{ \frac{d}{3} }{4} = \frac{d}{12} }$

"t2" be time for next two journeys.

Then,

$= > \bold{d - \frac{d}{3}= 2t2 + 6t2} \\ = > \bold{ \frac{2d}{3} = 8t2} \\ = > \bold{t2 = \frac{d}{12} }$

$\bold{Average \: Velocity = \frac{total \: distance}{total \: time} } \\ = \frac{d}{t1 + 2t2} \\ = \frac{d}{ \frac{d}{12} + \frac{2d}{12} } \\ = \bold{ \boxed{4m/s}}$

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Hope, it helps you.