Question

A body travelling at 4 m/s changes its velocity to 2 m/s with uniform acceleration. In the meantime, it covers a distance of 6m. Find the acceleration.​

Answer 1

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Answer 2

Answer:

The acceleration of the body is -1 m/sec² .

Explanation:

Given that :

• Initial velocity = 4 m/sec
• Final velocity = 2 m/sec
• Distance travelled by body = 6 m

To find :

• Acceleration of body

Solution :

• Let, the initial velocity of body be u and its final velocity be v. Distance travelled by body be s. Then,

${v}^{2} - {u}^{2} = 2as$

• Here, initial velocity, u = 4 m/sec
• Final velocity, v = 2 m/sec
• Distance, s = 6 m
• Acceleration of the body is

${v}^{2} - {u}^{2} = 2as \\ {(2)}^{2} - {(4)}^{2} = 2a(6) \\ 4 - 16 = 12a \\ 12a = - 12 \\ a = - 1 \: m/ {sec}^{2}$

• Hence, body retardates at rate of 1 m/sec² .