Question

a body travelling with a velocity of 10 metre per second has an acceleration of -4 metre per second square find the velocity of the body after 10 second​

Answer 1

Answer:

Given -:

$\sf{Initial \:Velocity \:of\: a \:body \:=\: 10\: m/s}$

$\sf{Acceleration \:of \:the \:body\:=\:{-4\:m/s}^{2}}$

To find -:

$\sf{Velocity\:after\:10\:second\:of\:the\:body}$

$\sf{Or\: the\:final\:velocity\:of\:the\:body}$

Taken -:

$\sf{To\:find\:final\:velocity\: :}$

$\sf{\boxed{v=u+at}}$

$\sf{Where,}$

$\sf{v=Final\:velocity}$

$\sf{u=Initial\:velocity}$

$\sf{a=Acceleration}$

$\sf{t=Time}$

Solution -:

$\sf{:\implies{v=10\:m/s+({-4\:m/s}^{2}\times\:10s)}}$

$\sf{:\implies{v=10\:m/s+(-40\:m/s)}}$

$\sf{:\implies{v=10\:m/s-40\:m/s}}$

$\sf{:\implies{v=-30\:m/s}}$

Verification -:

To verify use the formula of Acceleration -:

$\sf{\boxed{a=\dfrac{v-u}{t}}}$

SOLUTION :

$\sf{:\implies{a=\dfrac{-30\:m/s-10\:m/s}{10\:s}}}$

$\sf{:\implies{a=\dfrac{-40\:m/s}{10\:s}}}$

$\sf{:\implies{a={-4\:m/s}^{2}}}$

So , the Acceleration has came ${-4\:m/s}^{2}$ . A/Q the Acceleration is ${-4\:m/s}^{2}$ .

Hence , the answer is verified .

Answer -:

So , the speed of the body after 10 seconds is -30 m/s .

Or , the final velocity is -30 m/s .