A body travelling with a velocity of 60 ms-1 gains an acceleration of 100 ms-2. Calculate distance travelled by the body in 15 seconds.
Answers
Answered by
9
According to the question,Initial velocity = 60m/secAcceleration = 100m/secTime taken = 15 secondsDistance travelled = ?
According to the second equation of motion that is S = ut + 1/2 Xat-2S = ( 60 X 15 ) + 1/2 X 100 X 15squareS = 900 + 1/2 X 100 X 225S = 900 + 1/2 X 22500S = 900 + 11250S = 12150
Hence , the distance travelled by the body in 15 seconds = 12150 metres
According to the second equation of motion that is S = ut + 1/2 Xat-2S = ( 60 X 15 ) + 1/2 X 100 X 15squareS = 900 + 1/2 X 100 X 225S = 900 + 1/2 X 22500S = 900 + 11250S = 12150
Hence , the distance travelled by the body in 15 seconds = 12150 metres
Answered by
6
Use the equation s=ut+at²/2
On substituting the values of u, t and a you get
s=12150m
If found helpful please do mark
On substituting the values of u, t and a you get
s=12150m
If found helpful please do mark
Similar questions