Question

A body travelling with a velocity of 60 ms-1 gains an acceleration of 100 m/s square Calculate distance travelled by the body in 15 seconds.

Answer 1

Given:

Initial velocity of body, u= 60 m/s

Acceleration of body, a= 100 m/s²

To Find:

Distance travelled by the body in 15 seconds

Solution:

We know that,

• According to second equation of motion for constant acceleration,

$\orange{\boxed{\bf{s=ut+\dfrac{1}{2}at^{2}}}}$

where,

u is initial velocity

a is acceleration

s is displacement

t is time taken

$\rule{190}{1}$

Let the distance travelled by body in 15s be s

So,

$\longrightarrow\rm{s=ut+\dfrac{1}{2}at^{2}}$

$\longrightarrow\rm{s=60(15)+\dfrac{1}{2}(100)(15)^{2}}$

$\longrightarrow\rm{s=900+\dfrac{1}{2}(100)(225)}$

$\longrightarrow\rm{s=900+\dfrac{22500}{2}}$

$\longrightarrow\rm{s=900+11250}$

$\longrightarrow\rm\green{s=12150\:m}$

Hence, the distance travelled by the body in 15 seconds is 12150 m.

Answer 2

Given:-

• Initial velocity (u) of body = 60m/s

• Acceleration (a) of body =100m/s²

• Time taken = 15s

To Find:-

• Distance (s) covered by body.

Solution :-

By using 2nd equation of motion.

➦ s = ut +1/2at²

➭ s = 60×15+1/2 × 100× 15²

➭ s = 900+1/2×100× 225

➭ s = 900+50×225

➭ s = 900+11250

➭ s = 12150 m.

➭ s = 12150/1000 = 12.15km

∴ The distance covered by body is 12.15km