a body travelling with uniform acceleration crosses two points point A and B with velocity is 30 M per second and 40 m per second respectively find speed of body at midpoint a and b
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assuming distance of midpoint from A and B to be x and velocity at A is u = 30, at mid point as V1 and at B as V2=40
V1^2-u^2 = 2ax
V2^2-V1^2 = 2ax
which implies V1^2-u^2 = V2^2-V1^2
2V1^2 = V2^2+u^2 = 40^2+30^2
V1 = sqrt ((1600+900)/2) = 35.35534
V1^2-u^2 = 2ax
V2^2-V1^2 = 2ax
which implies V1^2-u^2 = V2^2-V1^2
2V1^2 = V2^2+u^2 = 40^2+30^2
V1 = sqrt ((1600+900)/2) = 35.35534
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