Question

A body travelling with uniform acceleration crosses two points A and B with velocities 20m/s and 30m/s find the velocity at its mid point.

Answer 1

It is √[20²+30²]/2 = √650 = 25.49 m/s

Answer 2

AB = s
     2 a s= (30² - 20² ) = 500          s = 250/a

AB/2 = s/2
       2 a s/2  = (v² - 20²) 
       250 = v²  - 400    =>  v = √650 m/s