Question

A body travelling with velocity of 60m/s^-1 gains an acceleration of 100m/s^-2. Calculate the distance travelled by the body in 15 seconds. Please show the steps as well.

Answer 1

Explanation:

Initial velocity = u = 60 m/s

Acceleration = a = 100 m/s²

Time = t = 15 seconds

Distance travelled S = ut + (1/2) at²

⇒ 60 * 15 + (1/2) * 100 * (15)²

⇒ 900 + 11250

⇒ 12150 m

Therefore,

Distance covered = 12150 m (or) 12.15 km

Hope it helps!

Answer 2

Answer:

Explanation:

Solution,

Here, we have

Initial velocity of body, u = 60 m/s

Acceleration of body, a = 100 m/s²

Time taken by particle, t = 15 seconds

To Find,

Distance traveled, s = ??

According to the 2nd equation of motion,

we know that,

s = ut + 1/2 × at²

On putting all the values, we get

⇒ s = ut + 1/2 × at²

⇒ s = 60 × 15 + 1/2 × 100 × 15²

⇒ s = 900 + 1/2 × 100 × 225

⇒ s = 900 + 50 × 225

⇒ s = 900 + 11250

⇒ s = 12150 m

Hence, the distance traveled by the body in 15 seconds is 12150 m.