A body travels 10 m in first three seconds and
15 m in the next four seconds. What is the
velocity at the end of 8 second?
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A body travels 10 m in the 1st 3 seconds and 15 m in the next 4 seconds. What is the velocity at the end of 8 seconds?
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Let u be initial velocity and a be uniform acceleration .
For motion in first 3s, we have,
10=3u+(1/2)a(9) …………(1)
For motion in first (3+4)s
25=3u+(1/2)a(49)…………(2)
(2)-(1) gives
15=(1/2)a(40)=20a OR
a=3/4 m/s^2……….(3)
Using this value in (1)
10=3u+(1/2)(3/4)(9)
10= 3u+(27/8) Therefore,
u=(53/24) m/s
The velocity at the end of 8s,
v=u+at
v=(53/24)+(3/4)(8)=[ (53/24)+6]m/s
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