A body travels 12km west ,6km north and 8km east . calculate its distance and displacement
Answers
Answer:
Distance depends on the path. So if the points are o, w, n….then ‘o’ to west ‘w’ that is ‘ow’ = 6 km and like that’w’ to ‘n’ “wn”=8 km
Now the distance will be the total of (‘ow’+‘wn’)= 6+8= 14 km
But displacement does not depend on the path the body passes, instead it depends on initial and ending point..
If we consume a triangle connecting the point o, w, n… then it will be an equiangular triangle… and the initial point of movement of that body is ‘o’ and and the ending point is ‘n’
So the displacement of the body will be ‘o’ to ’n’ that is ‘on’ which is hypotenuse of the equitrianglur triangle.. now to get the value of ‘on’ u have to apply ‘Pithagoras’s law’—
on^2=ow^2+wn^2=6^2+8^2=36+64=100
on^2=100
And, on=10km (displacement
l hope it will help u
