A body travels 200 CM in first 2 seconds and 220 CM in the next 5 second calculate the velocity at the end of last 7 seconds from start.
This is the question of Stalin Malhotra book of physics.
Any one who answer this question by full process and in correct way I mark his/her answer as a brainlist
Answers
Answered by
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there would be two answer
if the acceleration is constant then the formula will be 200+220/5+7
if the acceleration is not constant the the formula will be dx/dt
if the acceleration is constant then the formula will be 200+220/5+7
if the acceleration is not constant the the formula will be dx/dt
cenanktpa9s1r:
no wrong answer
what is it??
2.2m/s
Answered by
0
Case 1 --
Distance travelled = 200 cm
Time taken = 2 seconds
Case 2 --
Distance travelled = 220 cm
Time taken = 5 seconds
Total distance = 200 cm + 220 cm
= 420 cm [ As 1 cm = 1 / 100 m ]
= 420 / 100 m
= 4.2 m
Total time taken = 2 seconds + 5 seconds
= 7 seconds
Average velocity = Total displacement / Total time
Average velocity = Total distance with directiom / Total time
Average velocity = 4.2 m / 7s
= 0.6 m
Hope it helps. Please mark my answer as the
BRILLIANIST
ANSWER.
Distance travelled = 200 cm
Time taken = 2 seconds
Case 2 --
Distance travelled = 220 cm
Time taken = 5 seconds
Total distance = 200 cm + 220 cm
= 420 cm [ As 1 cm = 1 / 100 m ]
= 420 / 100 m
= 4.2 m
Total time taken = 2 seconds + 5 seconds
= 7 seconds
Average velocity = Total displacement / Total time
Average velocity = Total distance with directiom / Total time
Average velocity = 4.2 m / 7s
= 0.6 m
Hope it helps. Please mark my answer as the
BRILLIANIST
ANSWER.
What is the answer.
Are bhai answer kya hai
bata to sahi
2.2m/s
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Yah answer sahi hai
Hey cenaktpa9s1r Please mark my answer as the BRILLIANIST ANSWER. Also see your earlier questions also I had answered them also so also mark my answer as the BRILLIANIST ANSWER in that also.
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