Physics, asked by nishantsuman, 1 month ago

A body travels 200 cm in the first 2 s and 220 cm in the next 5 s. Calculate the velocity at the end of the seventh second from the start. (Ans. 2.22 m/s)

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Answers

Answered by thetrueprogrammer
3

Answer:

The body seems to decelerate, so the velocity should be less than 1 after 7 sec. , please check if Ans. is 2.22 or not.

Here is what I think

Explanation:

s1 = 200 cm = 2 m

t1 = 2 sec.

therefore, u = 2/2 = 1 m/s

s2 = 220 cm = 2.2 m

t2 = 5 sec.

therefore, v = 2.2/5 = 0.44 m/s

now, a = (v - u) ÷ t

= (0.44 - 1) ÷ (5 - 2)

= -0.66 ÷ 3 = -0.22 m/s^2

since a = -0.22 m/s^2

therefore, by 1st equation of motion

v = u + a.t

= 0.44 + (-0.22)×(5-7)

= 0.44 - 0.44

= 0

therefore the body comes to rest after 7 seconds.

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