Question

a body travels 200 cm in the first 2 second and 220cm in the next 5 second calculate the velocity at the end of the seventh second from the start
solve this

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Answer 1

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For case 1.

200=2u+2a

u+a=100....(1)

For case 2. .i.e. next 4 seconds, we have distance =420 cm and time =6 s

420=6u+18a

u+3a=70....(2)

Solving equation 1 and 2, we get,

u=115 cm/s and a=−15 cm/s

2

Now by

v=u+at

v=115−15×7

v=10 cm/s

Answer 2

Answer:

Firstly convert cm to m

200/100 = 2m

220/100 = 2.2m

Velocity = Displacement/ time taken

= 2+2.2/2+5

= 4.2/7

= 0.6 m/s