A body travels 200 cm in the first 2s and 220 cm in the next 5s.Calculate the velocity at the end of the seventh second from the start.
Adityaadidangi:
7 m/s
Nkravi..did u get d answer..
Aaditya ..answer cannot be 7 m s^-1..
Under any circumstances..
Answers
Answered by
0
heya.....
HI there !!
Time = t₁ = 2 sec
Time = t₂ = 5 sec
Total time = t₁ + t₂
= 7 sec
Distance traveled = 220 + 200 = 420 cm = 4.2 m
Speed = distance / time
= 4.2 / 7
= 0.6 m/s
tysm.#gozmit
HI there !!
Time = t₁ = 2 sec
Time = t₂ = 5 sec
Total time = t₁ + t₂
= 7 sec
Distance traveled = 220 + 200 = 420 cm = 4.2 m
Speed = distance / time
= 4.2 / 7
= 0.6 m/s
tysm.#gozmit
dude I'm an IITan
are you in 9th class?
I'm new here
and you?
you are a student of biology
good dude
but recheck the question
Answered by
0
Hi..
Hope this helps u!!
Hope this helps u!!
Attachments:
See the attachment..
in second time when you write
220 = 5u + 1/2a(25)
velocity is change
and it's after 2sec
v = u + 2a
now solve it
K ..thanks..
change it now dude
your answer
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