A body travels 200 cm in the first two seconds and 220 cm in the next four second. The velocity at the end of the seventh second from the start will be (acceleration is constant)
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Answer:
Hint: First of all, find the initial velocity and acceleration of the body by using the second equation of motion. Then find the velocity at 7th sec by using the first equation of motion and the obtained values of initial velocity and the acceleration of the body.
Explanation:
Formulae used: s=ut+12at2
, v=u+at
Given at time t=2 sec
, distance covered by the body s=200 cm
Complete step-by-step solution -
We know the formulae for second equation of motion i.e., s=ut+12at2
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