Question

A body travels 200cm in first two seconds and 220 cm in next four seconds.What will be the velocity at the end of the seventh second.

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Answer 1

Explanation:

s=ut+21at2

For case 1.

200=2u+2a

u+a=100....(1)

For case 2. .i.e. next 4 seconds, we have distance =420 cm and time =6 s

420=6u+18a

u+3a=70....(2)

Solving equation 1 and 2, we get, 

u=115 cm/s and a=−15 cm/s2

Now by 

v=u+at

v=115−15×7

v=10 cm/s

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