Question

a body travels 2m in first two seconds, and 2.2m in next four seconds,what will be the distance traveled in seventh second of its motion?​

Answer 1

Answer:Since in t=2s, distance covered s=2m we have ,

s=ut+12at2

2=u×2+12a×22

or u+a=1-----(i)

As the distance covered in t=2s to 6s is 2.2m We have

2.2=u(6−2)+12a(62−22)

2u+8a=1.1------(ii)

From equation (i) and (ii)

u=1.15ms−1

a=−0.15ms−2

From the relation v=u+at, We have on putting,

u=1.15ms−1,a=−0.15ms−2 and t=7s

v=1.15+(−0.15)×7

=0.10ms−1

Explanation: