Question

a body travels 4 km towards north then he turns to his right and travels another 4 kilometre before coming to rest calculate the total distance and total displacement
plz explain the answer after writing it​

Answer 1

Answer:

Displacement=4$\sqrt{2}$ km

Distance=8 km

Explanation:

The distance travelled by a body is the length of the path it has taken.

According to the question, the body travels 4km, turns right, and travels 4 km again.

Therefore, distance=4km+4km=8km

Displacement is the shortest path between the initial and final points. If we draw a figure for this, it forms a right angle triangle with perpendicular sides 4km each.

Using Pythagoras theorem, we will get

Hypotenuse(displacement)=4$\sqrt{2}$km

Answer 2

Answer:

total distance= 8 km

displacement= 4√2 km

Explanation:

total distance = 4km +4km = 8 km

ABC is a right triangle,

so , AC =√AB^2 +BC^2

= √ (4)^2 + (4)^2

=√16 + 16

=√32

= 4√2.

( you can even right the value of √2 , which is approximately equal to 1.414)

so displacement can also be written as

4 x 1.414 = 5.656 =5.7 (approx.)