A body travels a distance of 15m from A to B and then moves a distance of 20m at right angles to AB. Calculate total distance covered and the displacement.
Give Answer In Full Step Or Method.
Answers
Answered by
573
Let the final point be C
Thetefore,Total Distance=AB+BC
Distance=15m +20m
Distance=35m
Displacement=Hypotenous of Triangle ABC
Displacement =(AC)^2=(AB)^2+(BC)^2
=AC^2=15^2+20^2
=AC^2=225+400
=AC^2=625
Therefore,AC=ROOT625
AC=25m
Thetefore,Total Distance=AB+BC
Distance=15m +20m
Distance=35m
Displacement=Hypotenous of Triangle ABC
Displacement =(AC)^2=(AB)^2+(BC)^2
=AC^2=15^2+20^2
=AC^2=225+400
=AC^2=625
Therefore,AC=ROOT625
AC=25m
Answered by
163
Answer:
Distance = 35
Displacement≠ 25
Explanation:
Follow the steps shown in picture
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