Question

A body travels a distance of 15m from A to B and then moves a distance of 20m at right angles to AB. Calculate the total distance traveled and the displacement.​

Answer 1

Answer:

distance = 15 + 20 = 35

displacement =

$AC^{2}$ = $BC^{2}$ + $AB^{2}$ (PYTHAGORAS PROPERTY)

$AC^{2}$ = $15^{2} + 20^{2}$

      = 225 + 400

      = 625

AC = $\sqrt{625}$

     = 25

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Answer 2

Answer:

total distance travelled is =35

displacement of the body =25

Explanation:

In the figure

AB+BC is distance

AC IS displacement

distance travelled is the complete path travelled by the body = 15+20=35

displacement is the shortest path between any two points = 25