Question

a body travels a distance of 20m in the 7th second.how much distance shall it travels in the 15th second

Answer 1

20×15/7
20×2.142
42.84
So the body will.cover 42.84m in 15th second
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Answer 2

The equation for position time relation is s=ut+at²/2
s=ut+at²/2
20=7u+49a/2
40=14u+49a
40=7(2u+7a)
40=7(2u+7×v-u/7)
40=7(2u+v-u)
40=7(v+u)
40/7=v+u

s=ut+at²/2
s=15u+225a/2
2s=30u+225a
2s=15(2u+15(v-u/15))
2s=15(2u+v-u)
2s=15×40/7
2s=86m  (estimate, real value is 85.7 )
s=86/2=43.
If 2s=85,
s=42.5m
∴distance travelled is 43 or 42.5 km.(Value depends on which estimate is taken)

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