Question

A body travels a distance of 6m from A to B and then moving a distance of 8m at right angles to AB. The displacement of the body would be:
A. 20m
B. 30m
C. 10m
D. 40m

Answer 1

Answer:

Option C.

Explanation:

 Body firstly starts from A towards and covers 6 m. Then, it moves 8 m towards the path perpendicular to AB.

Using Pythagoras theorem :

Displacement^2 = 8^2 + 6^2 m^2

Displacement^2 = 100 m^2

Displacement = 10 m

Answer 2

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$\huge\bold{\mathtt{QUESTION}}$

➡ A body travels a distance of 6m from A to B and then moving a distance of 8m at right angles to AB. The displacement of the body would be ?

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$\huge\bold{\mathtt{SOLUTION}}$

☯ It is given that the body travels from A to B ( 6 m ) and then from B to C ( 8 m ) .

☯ Find - Displacement of the body

☯ We know that DISPLACEMENT is the shortest distance covered by a particular body.

↔ Here shortest distance travelled will be from A to C ( hypotenuse )

☯ $\sf {AB}^{2} + {BC}^{2} = {AC}^{2}$

↪ $\sf {6}^{2} + {8}^{2} = {AC}^{2}$

↪ $\sf 36 + 64 = {AC}^{2}$

↪ $\sf AC = \sqrt 100$

↪ $\sf AC = 10\:m$

$\large{\boxed{\mathtt{Displacement\:=\:10\:m}}}$

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