A body travels a distance s1 with velocity V1 and
distance S2 with velocity v2 in the same direction
Calculate the average velocity of the body.
Answers
Answer:Average velocity=
Totaltime
Totaldisplacement
=
t
1
+t
2
(S
1
+S
2
)
=
(
V
1
S
1
+
V
2
S
2
)
(S
1
+S
2
)
Hence,
option (D) is correct answer.
Explanation:
Time taken by the body to travel s1 distance= S1/V1 seconds
Time taken by the body to travel s2 distance = S2/V2 seconds
Total time taken by the body to travel = (s1/v1) + (s2/v2) equals to (s1v2 + s2v1) divides by (v1 + v2)
Therefore, total displacement = s1 + s2
Average velocity= (s1 + s2) / [ (s1v2 + s2v1)
divides by (v1 + v2) = (s1 + s2) (v1 + v2)
divided by (s1v2 + s2v1) .
= (s1v1 + s2v2) + (s1v2 +s2v1)
divided by (s1v2 + s2v1) .
= [ (s1v1 + s2v2) / (s1v2 + s2v1) ] + [ (s1v2 +s2v1) / (s1v2 + s2v1) ] .
= [ (s1v1 + s2v2) / (s1v2 + s2v1) ] + 1
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