Question

A body travels a distance s1 with velocity v1 and distance s2 with velocity v2 in same direction. Calculate average velocity of body

Answer 1

Answer:

Explanation:

Here is your answer

Answer 2

Answer:

$\frac{S_1+S_2}{\frac{S_1}{V_1} +\frac{S_2}{V_2} }$

Explanation:

Given:

Body moves along a path in the same direction over a distance $S_1$ with velocity $V_1$ and a distance $S_2$ with velocity $V_2$.

To find:

Average velocity

Solution:

The displacement is only the difference between the locations of the two marks and is unrelated to the route used to get there. The total length of the path between the two markings, however, is the distance travelled.

To calculate average speed, divide the total distance travelled by the object by the time it took to complete the distance.

It has m/s units and is a vector quantity.

Because displacement is always smaller than or equal to distance, average velocity is always less than or equal to average speed.

$AverageVelocity=\frac{Total Displacement​ }{TotalTime}$

Now as given in the question, substituting the values

$=\frac{S_1+S_2}{t_1+t_2}\\=\frac{S_1+S_2}{\frac{S_1}{V_1} +\frac{S_2}{V_2} }$

How is average velocity different from instantaneous velocity?

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