Question

A body travels from 5m/s and travels a distance of 200 m with an acceleration of 9cm/s² find the final velocity. ​

Answer 1

Answer:

the final velocity is 7.81m/s

Explanation:

As here, u=5m/s, S=200m, a=9 cm/s^2 =0.09m/s^2

we know that,

${v }^{2} = {u}^{2} + 2as$

on substituting the values

we get,

${v}^{2} = 25 + 2 \times 200 \times .09$

${v}^{2} = 61$

$v = \sqrt{61} = 7.81m {s }^{ - 1}$