Question

A body travels from a to b at 40m/s and from b to a at 60 m/s. calculate the average speed and average velocity

Answer 1

Hope u like my process
=====================
=>Let the distance from a to b be x m

=> Total distance travelled = 2x m

=> Speed from a to b = 40 m/s

=> time taken while travelling from a to b

$= \bf \: \frac{distance }{speed} = \frac{x}{40} \: sec$

=> speed from b to a = 60 m/s

=> time taken while travelling from b to a

$= \bf \: \frac{distance}{speed} = \frac{x}{60} \: \: sec$

=> Total time taken

$= \bf \: \frac{x}{40} + \frac{x}{60} = \frac{5x}{120} = \frac{x}{24} \: \: sec$

=> Average speed

$= \bf \: \frac{distance}{time} = \frac{2x}{ \frac{x}{24} } = 48 \: \: m {s}^{ - 1}$


______________________
=> Total displacement = x - x =0 m

=> Average velocity

$= \bf \: \frac{displacement}{time} = \frac{0}{ \frac{x}{24} } = 0 \: \: m {s}^{ - 1}$
___________________________
Hope this is ur required answer

Proud to help you

Answer 2

Answer:

Hope u like my process

=====================

=>Let the distance from a to b be x m

=> Total distance travelled = 2x m

=> Speed from a to b = 40 m/s

=> time taken while travelling from a to b

= \bf \: \frac{distance }{speed} = \frac{x}{40} \: sec=

speed

distance

=

40

x

sec

=> speed from b to a = 60 m/s

=> time taken while travelling from b to a

= \bf \: \frac{distance}{speed} = \frac{x}{60} \: \: sec=

speed

distance

=

60

x

sec

=> Total time taken

= \bf \: \frac{x}{40} + \frac{x}{60} = \frac{5x}{120} = \frac{x}{24} \: \: sec=

40

x

+

60

x

=

120

5x

=

24

x

sec

=> Average speed

= \bf \: \frac{distance}{time} = \frac{2x}{ \frac{x}{24} } = 48 \: \: m {s}^{ - 1}=

time

distance

=

24

x

2x

=48ms

−1

______________________

=> Total displacement = x - x =0 m

=> Average velocity

= \bf \: \frac{displacement}{time} = \frac{0}{ \frac{x}{24} } = 0 \: \: m {s}^{ - 1}=

time

displacement

=

24

x

0

=0ms

−1

___________________________

Hope this is ur required answer

Proud to help you