Question

a body travels with a speed of 5 metre per second for 2 seconds and with a speed of 12 metre per second for the next 5 second. distance travelled by the particle is​

Answer 1

AnswEr :

As per the provided information in the given question, it has been stated that the body travels with a speed of 5 m/s for 2 seconds and with a speed of 12 m/s for the next 5 second. We've been asked to calculate the distance travelled by the particle.

Here, there are two cases firstly it travels with a speed of 5 m/s for 2 seconds and then it travels with a speed of 12 m/s for the next 5 second. Basically, we need to calculate distance travelled in both cases to find the resultant distance travelled.

First case ::

In the first case, the speed of the body is 5 m/s and the time taken is 2 seconds. As we know that,

$\longrightarrow \boxed{ \tt{ s = v \times t }}$

• v denotes speed
• s denotes distance
• t denotes time

$\longrightarrow \boxed{ \tt{ S_1 = V_1 \times T_1 }} \\ \\ \longrightarrow \tt{ S_1 =\Big (5 \times 2 \Big) }\\ \\ \longrightarrow \tt{ S_1 = 10 \; m \dots (1) }$

Second case ::

In the first case, the speed of the body is 12 m/s and the time taken is 5 seconds. As we know that,

$\longrightarrow \boxed{ \tt{ s = v \times t }}$

• v denotes speed
• s denotes distance
• t denotes time

$\longrightarrow \boxed{ \tt{ S_2 = V_2 \times T_2 }} \\ \\ \longrightarrow \tt{ S_2 =\Big (12 \times 5 \Big) }\\ \\ \longrightarrow \tt{ S_2 = 60 \; m \dots (2) }$

Now, the sum of the distance travelled in the both cases will be the distance travelled by the particle.

$\longrightarrow \tt { Distance\; travelled = S_1 + S_2} \\ \\ \longrightarrow \tt { Distance\; travelled = \Big ( 60 + 10 \Big ) \; m} \\ \\ \longrightarrow \underline{\boxed{\tt { Distance\; travelled = 70 \; m}}} \; \red{\bigstar}$

Therefore, the distance travelled by the particle is 70 m.