Question

a body travels with a speed of v,from a to b returns with a speed of v,from a to b. derive an expression for the average speed of the body

Answer 1

Answer:

Now, let the distance between A & B be 'd'.

We're gonna use the formula, (Distance)=(Speed)(Time).

Time taken to go from A to B is t1=d/V1.

Time taken to come from B to A is t2=d/V2.

Now, you know that average velocity is (total distance)/(total time).

Then, V(average)=(2d)/(t1+t2)=\frac{2d}{\frac{d}{V1}+\frac{d}{V2}}

V1

d

+

V2

d

2d

. You get V(average)=2(V1)(V2)/(V1+V2