Question

A body travelsfrom A toBat40m/s and from BtoA 60m/s.Calculate the acerage speed and average velocity

Answer 1

average speed will be 48 m/s
average velocity will be 0

Answer 2

Hii..
Here is your answer

Solution:-
Let the distance travelled from A to B be x.
Speed from A to B=40m/s
Time =D/S
$= > \frac{x}{40}$
Let the distance from B to A also be x.
Speed from B to A =60m/s
Time =D/S
$= > \frac{x}{60}$
Now,
Total distance=x + x=2x
Total Time =
$= > \frac{x}{40} + \frac{x}{60} \\ = > \frac{3x + 2x}{120}$
$= > \frac{5x}{120}$
So,
$average \: speed = \frac{total \: distance}{total \: time}$
$= > \frac{2x}{ \frac{5x}{120} } \\ = > \frac{2x \times 120}{5x}$
$= > \frac{240x}{5x} \\ = > 48$ Therefore,
Average speed=48km/h
Now,
To find average velocity we need Displacement and time.

Displacement is O because he returned to the place from when he start.
$= > average \: velocity = \frac{displacement}{time}$
$= > \frac{0}{ \frac{5x}{120} } \\ = > \frac{ 0 \times 120}{5x}$
$= > \frac{0}{5x} = 0$
Hence,
Average velocity=0m/s

Hope it helps uh...✌️✌️✌️