A body under the action of a force F = (3i + 2j -4k) N covers a displacement s = (3i – 2j +4k) m. Calculate the work done.
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0
Answer:
u=kt
dt
dx
=kt
⇒dx=ktdt
or∫
0
x
dx=∫
0
3
ktdt
x=k(
2
t
2
)
0
3
=k(
2
9
)=2(
2
9
)=9m
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